To score good marks in the SBI PO exam, daily practice for the reasoning section is important. Candidates must focus on exact, exam-patterned questions that involve Puzzles, Seating Arrangements, Coding-Decoding, and Syllogisms. Consistent practice and speed are important to ace this section in the exam.
SBI PO Reasoning Questions
If you want to crack SBI PO 2026 . Below are 30 most important questions based on the pattern followed in the previous exam and the most frequently asked questions.
Study the following information carefully and answer the questions given below.
Seven Persons- A, S, Y, H, R, I and V were born in seven different years - 1987, 1979, 1978, 2001, 1982, 2004 and 1990, but not necessarily in the same order. Also, their age will be calculated based on the year 2018. Only one person is born in a year.
Note: If it is given that the age of one person is equal to the last two digits of the year in which another person is born, then it can be in any sequence. For example, if S’s age is equal to the last two digits of the A’s born year, which is 1987, then the age of S is either 78 or 87.
The age of H is equal to the last two digits of the year in which V was born. A was born exactly between I and Y. Only two persons were born between I and the one who was born immediately before Y. Y was born before V but after S. Y was not born in 1987. R was born immediately after the one whose age is an even number but not in a prime-numbered year.
Q1. Which of the following statements is/are true regarding the one who was born exactly between the one who was born immediately before I and the one whose age is three years more than Y?
I. He was born in 1982
II. He is person Y
III. His age is 31 years
(A). Only III
(B). Both I and III
(C). All I, II and III
(D). Both I and II
(E). Only II
Answer: D
Solution
Final Arrangement
| Years | Persons | Age |
| 1978 | H | 40 |
| 1979 | S | 39 |
| 1982 | Y | 36 |
| 1987 | A | 31 |
| 1990 | I | 28 |
| 2001 | R | 17 |
| 2004 | V | 14 |
Clue: The age of H is equal to the last two digits of the year in which V was born.
Inference: We have two possible cases:
| Years | Case 1 | Case 2 | ||
| Person | Age | Person | Age | |
| 1978 | H | 40 | 40 | |
| 1979 | 39 | 39 | ||
| 1982 | 36 | V | 36 | |
| 1987 | 31 | 31 | ||
| 1990 | 28 | H | 28 | |
| 2001 | 17 | 17 | ||
| 2004 | V | 14 | 14 | |
Clues: A was born exactly between I and Y. Only two persons were born between I and the one who was born immediately before Y. Y was born before V but after S. Y was not born in 1987.
Inference: Case 2 gets eliminated, and case 1a is introduced:
| Years | Case 1 | Case 2 | Case 1a | |||
| Persons | Age | Persons | Age | Persons | Age | |
| 1978 | H | 40 | S | 40 | H | 40 |
| 1979 | I | 39 | Y | 39 | S | 39 |
| 1982 | 36 | V | 36 | Y | 36 | |
| 1987 | A | 31 | I | 31 | A | 31 |
| 1990 | 28 | H | 28 | I | 28 | |
| 2001 | Y | 17 | 17 | 17 | ||
| 2004 | V | 14 | 14 | V | 14 | |
Clues: R was born immediately after the one whose age is an even number but not in a prime numbered year.
Inference: Case 1 gets eliminated here:
| Years | Case 1 | Case 1a | ||
| Persons | Age | Persons | Age | |
| 1978 | H | 40 | H | 40 |
| 1979 | I | 39 | S | 39 |
| 1982 | S | 36 | Y | 36 |
| 1987 | A | 31 | A | 31 |
| 1990 | S | 28 | I | 28 |
| 2001 | Y | 17 | R | 17 |
| 2004 | V | 14 | V | 14 |
Inference: Final arrangement is:
| Year | Persons | Age |
| 1978 | H | 40 |
| 1979 | S | 39 |
| 1982 | Y | 36 |
| 1987 | A | 31 |
| 1990 | I | 28 |
| 2001 | R | 17 |
| 2004 | V | 14 |
Both I and II
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Q2. Which of the following statements is not true?
(A). H was born before S
(B). R was born immediately after I
(C). V‘s age is an even number
(D). He was born after the one whose age is 36 years
(E). All are true
Answer: D
Solution
| Years | Persons | Age |
| 1978 | H | 40 |
| 1979 | S | 39 |
| 1982 | Y | 36 |
| 1987 | A | 31 |
| 1990 | I | 28 |
| 2001 | R | 17 |
| 2004 | V | 14 |
Clue: The age of H is equal to the last two digit of the year in which V was born.
Inference: We have two possible cases:
| Years | Case 1 | Case 2 | ||
| Person | Age | Person | Age | |
| 1978 | H | 40 | 40 | |
| 1979 | 39 | 39 | ||
| 1982 | 36 | V | 36 | |
| 1987 | 31 | 31 | ||
| 1990 | 28 | H | 28 | |
| 2001 | 17 | 17 | ||
| 2004 | V | 14 | 14 | |
Clues: A was born exactly between I and Y. Only two persons were born between I and the one who was born immediately before Y. Y was born before V but after S. Y doesn’t born in 1987.
Inference: Case 2 gets eliminated and case 1a introduced:
| Years | Case 1 | Case 2 | Case 1a | |||
| Persons | Age | Persons | Age | Persons | Age | |
| 1978 | H | 40 | S | 40 | H | 40 |
| 1979 | I | 39 | Y | 39 | S | 39 |
| 1982 | 36 | V | 36 | Y | 36 | |
| 1987 | A | 31 | I | 31 | A | 31 |
| 1990 | 28 | H | 28 | I | 28 | |
| 2001 | Y | 17 | 17 | 17 | ||
| 2004 | V | 14 | 14 | V | 14 | |
Clues: R was born immediately after the one whose age is an even number but not in a prime numbered year.
Inference: Case 1 gets eliminated here:
| Years | Case 1 | Case 1a | ||
| Persons | Age | Persons | Age | |
| 1978 | H | 40 | H | 40 |
| 1979 | I | 39 | S | 39 |
| 1982 | S | 36 | Y | 36 |
| 1987 | A | 31 | A | 31 |
| 1990 | S | 28 | I | 28 |
| 2001 | Y | 17 | R | 17 |
| 2004 | V | 14 | V | 14 |
Inference: Final arrangement is:
| Year | Persons | Age |
| 1978 | H | 40 |
| 1979 | S | 39 |
| 1982 | Y | 36 |
| 1987 | A | 31 |
| 1990 | I | 28 |
| 2001 | R | 17 |
| 2004 | V | 14 |
Statement in option(d) is not true.
Study the following information carefully and answer the given questions:
Six persons- M, N, O, P, Q and R - are living in the three-floor building (but not necessarily in the same order). The ground floor is numbered as 1, the floor just above it is numbered as 2 and so on. Each floor has 2 flats in it i.e., Flat 1, Flat 2. Flat 1 of floor 2 is immediately above flat 1 of floor 1 and immediately below flat 1 of Floor 3. Flat 2 of Floor 2 is immediately above flat 2 of floor 1 and immediately below flat 2 of Floor 3. Flat 1 is exactly to the west of Flat 2. Each person likes different colour- Blue, Black, White, Red, Pink and Green.
M lives on an even number floor. The one who lives just below M in the same named flat likes white colour. One floor is between the one who likes white colour and the one who likes green colour. M and the one who likes green colour does not live in same named flat. O lives two floors above P. O and P does not live in same named flat. N likes green colour. R does not like white colour and no one lives east of R. O, P and M does not like red colour. P and M does not like pink colour. The one who likes red colour and the one who likes black colour does not live in same named flat.
Q3. Four of the following five are in the same group, who among the following does not belong to that group?
(A). O
(B). N
(C). M
(D). R
(E). P
Answer: E
Solution:
Final arrangement:
| Floor | Flat 1 | Flat 2 |
| 3 | O (Pink) | N (Green) |
| 2 | M (Black) | R (Red) |
| 1 | Q (White) | P (Blue) |
Clues: M lives on an even number floor. The one who lives just below M in the same named flat likes white colour. One floor is between the one who likes white colour and the one who likes green colour. M and the one who likes green colour does not live in same named flat.
Inference: Here we get two possible cases-
| Floor | Case 1 | Case 2 | ||
| Falt 1 | Flat 2 | Flat 1 | Flat 2 | |
| 3 | (Green) | (Green) | ||
| 2 | M | M | ||
| 1 | (White) | (White) | ||
Clues: O lives two floors above P. O and P does not live in same named flat. N likes green colour. R does not like white colour and no one lives east of R. O, P and M does not like red colour. P and M does not like pink colour. The one who likes red colour and the one who likes black colour does not live in same named flat.
Inference: Now case 2 will be eliminated and we get-
| Floor | Case 1 | Case 2 | ||
| Falt 1 | Flat 2 | Flat 1 | Flat 2 | |
| 3 | O (Pink) | N (Green) | N (Green) | O |
| 2 | M (Black) | R (Red) | R | M |
| 1 | Q (White) | P (Blue) | P | (White) |
Inference: The final arrangement is-
| Floor | Flat 1 | Flat 2 |
| 3 | O (Pink) | N (Green) |
| 2 | M (Black) | R (Red) |
| 1 | Q (White) | P (Blue) |
Except P, the rest live on prime-numbered floors.
Q4. The one who lives immediately above P in the same named flat, which colour does he like
(A). Red
(B). Green
(C). Black
(D). Blue
(E). None of these
Answer: A
Solution
Final Arrangement
| Floor | Flat 1 | Flat 2 |
| 3 | O (Pink) | N (Green) |
| 2 | M (Black) | R (Red) |
| 1 | Q (White) | P (Blue) |
Clues: M lives on an even number floor. The one who lives just below M in the same named flat likes white colour. One floor is between the one who likes white colour and the one who likes green colour. M and the one who likes green colour does not live in same named flat.
Inference: Here we get two possible cases-
| Floor | Case 1 | Case 2 | ||
| Falt 1 | Flat 2 | Flat 1 | Flat 2 | |
| 3 | (Green) | (Green) | ||
| 2 | M | M | ||
| 1 | (White) | (White) | ||
Clues: O lives two floors above P. O and P does not live in same named flat. N likes green colour. R does not like white colour and no one lives east of R. O, P and M does not like red colour. P and M does not like pink colour. The one who likes red colour and the one who likes black colour does not live in same named flat.
Inference: Now case 2 will be eliminated and we get-
| Floor | Case 1 | Case 2 | ||
| Falt 1 | Flat 2 | Flat 1 | Flat 2 | |
| 3 | O (Pink) | N (Green) | N (Green) | O |
| 2 | M (Black) | R (Red) | R | M |
| 1 | Q (White) | P (Blue) | P | (White) |
Inference: The final arrangement is-
| Floor | Flat 1 | Flat 2 |
| 3 | O (Pink) | N (Green) |
| 2 | M (Black) | R (Red) |
| 1 | Q (White) | P (Blue) |
The one who likes red colour lives immediately above P.
Q5. Which of the following options is correct?
(A). O likes pink colour
(B). Q lives on bottom most floor
(C). P likes blue colour
(D). N lives on third floor
(E). All are correct
Answer: E
Solution
Final Arrangement:
| Floor | Flat 1 | Flat 2 |
| 3 | O (Pink) | N (Green) |
| 2 | M (Black) | R (Red) |
| 1 | Q (White) | P (Blue) |
Clues: M lives on an even number floor. The one who lives just below M in the same named flat likes white colour. One floor is between the one who likes white colour and the one who likes green colour. M and the one who likes green colour does not live in same named flat.
Inference: Here we get two possible cases-
| Floor | Case 1 | Case 2 | ||
| Falt 1 | Flat 2 | Flat 1 | Flat 2 | |
| 3 | (Green) | (Green) | ||
| 2 | M | M | ||
| 1 | (White) | (White) | ||
Clues: O lives two floors above P. O and P does not live in same named flat. N likes green colour. R does not like white colour and no one lives east of R. O, P and M does not like red colour. P and M does not like pink colour. The one who likes red colour and the one who likes black colour does not live in same named flat.
Inference: Now case 2 will be eliminated and we get-
| Floor | Case 1 | Case 2 | ||
| Falt 1 | Flat 2 | Flat 1 | Flat 2 | |
| 3 | O (Pink) | N (Green) | N (Green) | O |
| 2 | M (Black) | R (Red) | R | M |
| 1 | Q (White) | P (Blue) | P | (White) |
Inference: The final arrangement is-
| Floor | Flat 1 | Flat 2 |
| 3 | O (Pink) | N (Green) |
| 2 | M (Black) | R (Red) |
| 1 | Q (White) | P (Blue) |
All are correct.
Q6. Who lives on third floor of flat 2?
(A). O
(B). R
(C). N
(D). M
(E). None of these
Answer: C
Solution
Final Arrangement
| Floor | Flat 1 | Flat 2 |
| 3 | O (Pink) | N (Green) |
| 2 | M (Black) | R (Red) |
| 1 | Q (White) | P (Blue) |
Clues: M lives on an even number floor. The one who lives just below M in the same named flat likes white colour. One floor is between the one who likes white colour and the one who likes green colour. M and the one who likes green colour does not live in same named flat.
Inference: Here we get two possible cases-
| Floor | Case 1 | Case 2 | ||
| Falt 1 | Flat 2 | Flat 1 | Flat 2 | |
| 3 | (Green) | (Green) | ||
| 2 | M | M | ||
| 1 | (White) | (White) | ||
Clues: O lives two floors above P. O and P does not live in same named flat. N likes green colour. R does not like white colour and no one lives east of R. O, P and M does not like red colour. P and M does not like pink colour. The one who likes red colour and the one who likes black colour does not live in same named flat.
Inference: Now case 2 will be eliminated and we get-
| Floor | Case 1 | Case 2 | ||
| Falt 1 | Flat 2 | Flat 1 | Flat 2 | |
| 3 | O (Pink) | N (Green) | N (Green) | O |
| 2 | M (Black) | R (Red) | R | M |
| 1 | Q (White) | P (Blue) | P | (White) |
Inference: The final arrangement is-
| Floor | Flat 1 | Flat 2 |
| 3 | O (Pink) | N (Green) |
| 2 | M (Black) | R (Red) |
| 1 | Q (White) | P (Blue) |
N lives on third floor of flat 2.
Q7. . Which of the following option is correct regarding P?
(A). P lives on second floor
(B). P lives on third floor
(C). No one lives west of P
(D). No one lives east of P
(E). None of these
Answer: D
Solution
Final Arrangement
| Floor | Flat 1 | Flat 2 |
| 3 | O (Pink) | N (Green) |
| 2 | M (Black) | R (Red) |
| 1 | Q (White) | P (Blue) |
Clues: M lives on an even number floor. The one who lives just below M in the same named flat likes white colour. One floor is between the one who likes white colour and the one who likes green colour. M and the one who likes green colour does not live in same named flat.
Inference: Here we get two possible cases-
| Floor | Case 1 | Case 2 | ||
| Falt 1 | Flat 2 | Flat 1 | Flat 2 | |
| 3 | (Green) | (Green) | ||
| 2 | M | M | ||
| 1 | (White) | (White) | ||
Clues: O lives two floors above P. O and P does not live in same named flat. N likes green colour. R does not like white colour and no one lives east of R. O, P and M does not like red colour. P and M does not like pink colour. The one who likes red colour and the one who likes black colour does not live in same named flat.
Inference: Now case 2 will be eliminated and we get-
| Floor | Case 1 | Case 2 | ||
| Falt 1 | Flat 2 | Flat 1 | Flat 2 | |
| 3 | O (Pink) | N (Green) | N (Green) | O |
| 2 | M (Black) | R (Red) | R | M |
| 1 | Q (White) | P (Blue) | P | (White) |
Inference: The final arrangement is-
| Floor | Flat 1 | Flat 2 |
| 3 | O (Pink) | N (Green) |
| 2 | M (Black) | R (Red) |
| 1 | Q (White) | P (Blue) |
No one lives east of P.
Study the following information and answer the questions below:
Six persons sit around a circular table but not necessarily in the same order. Three of them face inside while rest three faces outside the centre. All of them get different marks in an examination viz. 16, 18, 20, 25, 27 and 36 but not in the same order as given.
T sits second to the right of O and gets the marks which is cube of a number. One person sits between T and X who faces same direction as O. The one who gets double marks of O is an immediate neighbor of T.L sits second to the right of R who gets 7 marks less than T. L does not get highest marks. R and O faces opposite directions. Immediate neigbours of R facing same direction. K is not an immediate neighbor of X. The one who gets 16 marks sits second to the right of T but immediate left of the one who gets 25 marks. R doesn’t face inside
Q8. Who among the following sits second to the right of the one who gets 25 marks?
(A). R
(B). O
(C). K
(D). T
(E). None of these
Answer: C
Solution
T sits second to the right of O and gets the marks which is cube of a number. There are two possibilities. One person sits between T and X who faces same direction as O. The one who gets double marks of O is an immediate neighbor of T. There is only possibility that O gets 18 marks.
L sits second to the right of R who gets 7 marks less than T. L does not get highest marks. R and O faces opposite directions. Immediate neigbours of R facing same direction. K is not an immediate neighbor of X. R doesn’t face inside. From this condition case-1 will be eliminated.
The one who gets 16 marks sits second to the right of T but immediate left of the one who gets 25 marks. The final arrangement is-
K sits second to the right of L who gets 25 marks.
Q9. What is the difference between the marks get by X and O?
(A). 7
(B). 4
(C). 5
(D). 2
(E). None of these
Answer: D
Solution
T sits second to the right of O and gets the marks which is cube of a number. There are two possibilities. One person sits between T and X who faces same direction as O. The one who gets double marks of O is an immediate neighbor of T. There is only possibility that O gets 18 marks.
L sits second to the right of R who gets 7 marks less than T. L does not get highest marks. R and O faces opposite directions. Immediate neigbours of R facing same direction. K is not an immediate neighbor of X. R doesn’t face inside. From this condition case-1 will be eliminated.
The one who gets 16 marks sits second to the right of T but immediate left of the one who gets 25 marks. The final arrangement is-
X=16, O=18
Difference= 18-16=2
Q10. Who among the following sits second to the left of the one who gets fourth lowest marks
(A). O
(B). R
(C). K
(D). T
(E). None of these
Answer: B
Solution:
T sits second to the right of O and gets the marks which is cube of a number. There are two possibilities. One person sits between T and X who faces same direction as O. The one who gets double marks of O is an immediate neighbor of T. There is only possibility that O gets 18 marks.
L sits second to the right of R who gets 7 marks less than T. L does not get highest marks. R and O faces opposite directions. Immediate neigbours of R facing same direction. K is not an immediate neighbor of X. R doesn’t face inside. From this condition case-1 will be eliminated.
The one who gets 16 marks sits second to the right of T but immediate left of the one
who gets 25 marks. The final arrangement is-
R sits second to the left of L.
Study the following information carefully and answer the questions given below.
Eight boxes i.e., M, N, O, P, Q, R, S and T are placed one above the other. These boxes contain different dry-fruits i.e., Almonds, Cashews, Raisins, Dates, Figs, Walnuts, Saffron and Apricots but not necessarily in the same order.
The box which contains Cashews is placed just above S which is not placed at bottommost position. Three boxes are placed between S and O. There are two boxes which are placed between O and T. Not more than one box is placed between T and M. Maximum one box is placed between O and M. Q is placed third above M and contains Dates. Three boxes are placed between Q and P. One box is placed between P and S which contains Apricots. More than two boxes are placed between M and R. There are three boxes placed between the box which contains Apricots and the box which contains Saffron. One box is placed between the box which contains Saffron and the box which contains Figs. N does not contain Almonds and Walnuts. M does not contain Walnuts.
Q11. Which of the following box is placed at top?
(A). T
(B). Q
(C). P
(D). N
(E). O
Answer: B
Solution
Final Arrangement is
| Boxes- Dry Fruits |
| Q- Dates |
| N- Raisins |
| O- Saffron |
| M- Almonds |
| P- Figs |
| T- Cashew |
| S- Apricots |
| R- Walnuts |
Clues: Q is placed third above M and contains Dates. Three boxes are placed between Q and P. One box is placed between P and S which contains Apricots. The box which contains Cashews is placed just above S which is not placed at bottommost position.
Inference: Here we get three possible cases:
| Boxes- Dry Fruits | Boxes- Dry Fruits | Boxes- Dry Fruits |
| Case 1 | Case 2 | Case 3 |
| P | Q- Dates | Q- Dates |
| Cashew | Cashew | |
| S- Apricot | S- Apricots | |
| M | M | |
| Q- Dates | P | P |
| Cashew | ||
| S- Apricots | ||
| M |
Clues: Three boxes are placed between S and O. There are two boxes which are placed between O and T. Not more than one box is placed between T and M. Maximum one box is placed between O and M.
Inference: Case 1 gets cancelled here because not more than one box is placed between T and M. Case 3 gets cancelled here because maximum one box is placed between O and M.
| Boxes- Dry Fruits | Boxes- Dry Fruits | Boxes- Dry Fruits |
| Case 1 | Case 2 | Case 3 |
| P | Q- Dates | O |
| Cashew | ||
| S Apricot | O | Q Dates |
| T | M | T Cashew |
| Q Dates | P | S Apricots |
| T- Cashew | M | |
| O | S- Apricots | P |
| M |
Clues: More than two boxes are placed between M and R. There are three boxes placed between the box which contains Apricots and the box which contains Saffron. One box is placed between the box which contains Saffron and the box which contains Figs. N does not contain Almonds and Walnuts. M does not contain Walnuts.
Inference: Only place for raisins is left. Now, the final arrangement is here:
| Boxes- Dry Fruits |
| Q- Dates |
| N- Raisins |
| O- Saffron |
| M- Almonds |
| P- Figs |
| T- Cashew |
| S- Apricots |
| R- Walnuts |
Box Q is at top.
Q12. Which of the following statement is true?
(A). O contains Cashews
(B). Two boxes are placed between N and S
(C). R contains Walnuts
(D). S is placed just above T
(E). None is true
Answer: C
Solution
Final Arrangement
| Boxes- Dry Fruits |
| Q- Dates |
| N- Raisins |
| O- Saffron |
| M- Almonds |
| P- Figs |
| T- Cashew |
| S- Apricots |
| R- Walnuts |
Clues: Q is placed third above M and contains Dates. Three boxes are placed between Q and P. One box is placed between P and S which contains Apricots. The box which contains Cashews is placed just above S which is not placed at bottommost position.
Inference: Here we get three possible cases:
| Boxes- Dry Fruits | Boxes- Dry Fruits | Boxes- Dry Fruits |
| Case 1 | Case 2 | Case 3 |
| P | Q- Dates | Q- Dates |
| Cashew | Cashew | |
| S- Apricot | S- Apricots | |
| M | M | |
| Q- Dates | P | P |
| Cashew | ||
| S- Apricots | ||
| M |
Clues: Three boxes are placed between S and O. There are two boxes which are placed between O and T. Not more than one box is placed between T and M. Maximum one box is placed between O and M.
Inference: Case 1 gets cancelled here because not more than one box is placed between T and M. Case 3 gets cancelled here because maximum one box is placed between O and M.
| Boxes- Dry Fruits | Boxes- Dry Fruits | Boxes- Dry Fruits |
| Case 1 | Case 2 | Case 3 |
| P | Q- Dates | O |
| Cashew | ||
| S Apricot | O | Q Dates |
| T | M | T Cashew |
| Q Dates | P | S Apricots |
| T- Cashew | M | |
| O | S- Apricots | P |
| M |
Clues: More than two boxes are placed between M and R. There are three boxes placed between the box which contains Apricots and the box which contains Saffron. One box is placed between the box which contains Saffron and the box which contains Figs. N does not contain Almonds and Walnuts. M does not contain Walnuts.
Inference: Only place for raisins is left. Now, the final arrangement is here:
| Boxes- Dry Fruits |
| Q- Dates |
| N- Raisins |
| O- Saffron |
| M- Almonds |
| P- Figs |
| T- Cashew |
| S- Apricots |
| R- Walnuts |
"R contains Walnuts" - is the true statement.
Q13. Which of the following box is placed second above the box which contains Almonds?
(A). Q
(B). N
(C). M
(D). P
(E). S
Answer: B
Solution:
Final Arrangement
| Boxes- Dry Fruits |
| Q- Dates |
| N- Raisins |
| O- Saffron |
| M- Almonds |
| P- Figs |
| T- Cashew |
| S- Apricots |
| R- Walnuts |
Clues: Q is placed third above M and contains Dates. Three boxes are placed between Q and P. One box is placed between P and S which contains Apricots. The box which contains Cashews is placed just above S which is not placed at bottommost position.
Inference: Here we get three possible cases:
| Boxes- Dry Fruits | Boxes- Dry Fruits | Boxes- Dry Fruits |
| Case 1 | Case 2 | Case 3 |
| P | Q- Dates | Q- Dates |
| Cashew | Cashew | |
| S- Apricot | S- Apricots | |
| M | M | |
| Q- Dates | P | P |
| Cashew | ||
| S- Apricots | ||
| M |
Clues: Three boxes are placed between S and O. There are two boxes which are placed between O and T. Not more than one box is placed between T and M. Maximum one box is placed between O and M.
Inference: Case 1 gets cancelled here because not more than one box is placed between T and M. Case 3 gets cancelled here because maximum one box is placed between O and M.
| Boxes- Dry Fruits | Boxes- Dry Fruits | Boxes- Dry Fruits |
| Case 1 | Case 2 | Case 3 |
| P | Q- Dates | O |
| Cashew | ||
| S Apricot | O | Q Dates |
| T | M | T Cashew |
| Q Dates | P | S Apricots |
| T- Cashew | M | |
| O | S- Apricots | P |
| M |
Clues: More than two boxes are placed between M and R. There are three boxes placed between the box which contains Apricots and the box which contains Saffron. One box is placed between the box which contains Saffron and the box which contains Figs. N does not contain Almonds and Walnuts. M does not contain Walnuts.
Inference: Only place for raisins is left. Now, the final arrangement is here:
| Boxes- Dry Fruits |
| Q- Dates |
| N- Raisins |
| O- Saffron |
| M- Almonds |
| P- Figs |
| T- Cashew |
| S- Apricots |
| R- Walnuts |
Box N is placed second above the box which contains Almonds.
Q14. How many boxes are placed between the box which contains Walnuts and N?
(A). One
(B). Two
(C). Four
(D). Five
(E). Six
Answer: D
Solution:
Final Arrangement is here:
| Boxes- Dry Fruits |
| Q- Dates |
| N- Raisins |
| O- Saffron |
| M- Almonds |
| P- Figs |
| T- Cashew |
| S- Apricots |
| R- Walnuts |
Clues: Q is placed third above M and contains Dates. Three boxes are placed between Q and P. One box is placed between P and S which contains Apricots. The box which contains Cashews is placed just above S which is not placed at bottommost position.
Inference: Here we get three possible cases:
| Boxes- Dry Fruits | Boxes- Dry Fruits | Boxes- Dry Fruits |
| Case 1 | Case 2 | Case 3 |
| P | Q- Dates | Q- Dates |
| Cashew | Cashew | |
| S- Apricot | S- Apricots | |
| M | M | |
| Q- Dates | P | P |
| Cashew | ||
| S- Apricots | ||
| M |
Clues: Three boxes are placed between S and O. There are two boxes which are placed between O and T. Not more than one box is placed between T and M. Maximum one box is placed between O and M.
Inference: Case 1 gets cancelled here because not more than one box is placed between T and M. Case 3 gets cancelled here because maximum one box is placed between O and M.
| Boxes- Dry Fruits | Boxes- Dry Fruits | Boxes- Dry Fruits |
| Case 1 | Case 2 | Case 3 |
| P | Q- Dates | O |
| Cashew | ||
| S Apricot | O | Q Dates |
| T | M | T Cashew |
| Q Dates | P | S Apricots |
| T- Cashew | M | |
| O | S- Apricots | P |
| M |
Clues: More than two boxes are placed between M and R. There are three boxes placed between the box which contains Apricots and the box which contains Saffron. One box is placed between the box which contains Saffron and the box which contains Figs. N does not contain Almonds and Walnuts. M does not contain Walnuts.
Inference: Only place for raisins is left. Now, the final arrangement is here:
| Boxes- Dry Fruits |
| Q- Dates |
| N- Raisins |
| O- Saffron |
| M- Almonds |
| P- Figs |
| T- Cashew |
| S- Apricots |
| R- Walnuts |
Five
Q15. What is the position of O with respect to N?
(A). Just below
(B). Second below
(C). Second above
(D). Third above
(E). None of the above
Answer: A
Solution:
Final Arrangement is here:
| Boxes- Dry Fruits |
| Q- Dates |
| N- Raisins |
| O- Saffron |
| M- Almonds |
| P- Figs |
| T- Cashew |
| S- Apricots |
| R- Walnuts |
Clues: Q is placed third above M and contains Dates. Three boxes are placed between Q and P. One box is placed between P and S which contains Apricots. The box which contains Cashews is placed just above S which is not placed at bottommost position.
Inference: Here we get three possible cases:
| Boxes- Dry Fruits | Boxes- Dry Fruits | Boxes- Dry Fruits |
| Case 1 | Case 2 | Case 3 |
| P | Q- Dates | Q- Dates |
| Cashew | Cashew | |
| S- Apricot | S- Apricots | |
| M | M | |
| Q- Dates | P | P |
| Cashew | ||
| S- Apricots | ||
| M |
Clues: Three boxes are placed between S and O. There are two boxes which are placed between O and T. Not more than one box is placed between T and M. Maximum one box is placed between O and M.
Inference: Case 1 gets cancelled here because not more than one box is placed between T and M. Case 3 gets cancelled here because maximum one box is placed between O and M.
| Boxes- Dry Fruits | Boxes- Dry Fruits | Boxes- Dry Fruits |
| Case 1 | Case 2 | Case 3 |
| P | Q- Dates | O |
| Cashew | ||
| S Apricot | O | Q Dates |
| T | M | T Cashew |
| Q Dates | P | S Apricots |
| T- Cashew | M | |
| O | S- Apricots | P |
| M |
Clues: More than two boxes are placed between M and R. There are three boxes placed between the box which contains Apricots and the box which contains Saffron. One box is placed between the box which contains Saffron and the box which contains Figs. N does not contain Almonds and Walnuts. M does not contain Walnuts.
Inference: Only place for raisins is left. Now, the final arrangement is here:
| Boxes- Dry Fruits |
| Q- Dates |
| N- Raisins |
| O- Saffron |
| M- Almonds |
| P- Figs |
| T- Cashew |
| S- Apricots |
| R- Walnuts |
Box O is kept just below Box N.
Study the following information carefully and answer the questions given below:
K is the father-in-law of F. F is the brother-in-law of H who is not married. E is the grandson of G who has only two children of different genders. K and G are married couples. E is not the child of H. J is the mother of I and both are of same genders.
Q16. What is the ratio of male to female?
(A). 3:4
(B). 4:3
(C). 2:5
(D). 5:2
(E). None of these
Answer: B
Solution:
Final arrangement:
K(+)=G(-)
↓
H(+)→J(-)=F(+)
↓
E(+)→I(-)
Ratio of male to female is 4:3.
Q17. If H is married to Y, then how Y is related to J?
(A). Sister
(B). Aunt
(C). Sister-in-law
(D). Mother-in-law
(E). Niece
Answer: C
Solution:
Final arrangement:
K(+)=G(-)
↓
H(+)→J(-)=F(+)
↓
E(+)→I(-)
Sister-in-law
Q18. . How F is related to E?
(A). Uncle
(B). Nephew
(C). Brother-in-law
(D). Father
(E). Brother
Answer: D
Solution:
Final arrangement:
K(+)=G(-)
↓
H(+)→J(-)=F(+)
↓
E(+)→I(-)
F is the father of E
Study the following information carefully and answer the questions givenbelow:
Seven persons are arranged according to their payment for airplane ticket (in descending order) from left to right. Only one person pays more amount than C. Two persons pay between C and U. D either pays just higher amount or just lower amount than U. As many persons pays more amount than U as pay less amount than Z, B pays more amount than I. B does not pay the highest amount. D does not pay the second lowest amount. Person who pays second highest amount will have to pay Rs. 1500. M is one of the persons.
Q19. If B pays Rs. 600 less than the amount paid by C then how much amount will be paid by I
(A). Rs. 800
(B). Rs. 750
(C). Rs .1000
(D). Either Rs. 800 or Rs. 750
(E). None of these
Answer: D
Solution:
Explanation:
Clues: Only one person pays more amount than C. Two persons pay between C and U. D either pays just higher amount or just lower amount than U.
Inference: From the above conditions there are two possibilities i.e., Case 1 and Case 2.
Clues: As many persons pays more amount than U as pay less amount than Z. B pays more amount than I. B does not pay the highest amount. M is one of the persons.
Inference: Only one person remains i.e., M.
Clue: D does not pay the second lowest amount.
Inference: From the above conditions Case 1 is cancelled here as D will not pay the second lowest amount.
Clue: Person who pays second highest amount will have to pay Rs. 1500.
Inference: Final arrangement:
If B pays Rs. 600 less than C
Then amount paid by I may be either is Rs. 800 or Rs. 750
Q20. How many persons buys costlier tickets than M?
(A). Three
(B). Two
(C). One
(D). None
(E). None of these
Answer: D
Solution:
Explanation:
Clues: Only one person pays more amount than C. Two persons pay between C and U. D either pays just higher amount or just lower amount than U.
Inference: From the above conditions there are two possibilities i.e., Case 1 and Case 2.
Clues: As many persons pays more amount than U as pay less amount than Z. B pays more amount than I. B does not pay the highest amount. M is one of the persons.
Inference: Only one person remains i.e., M.
Clue: D does not pay the second lowest amount.
Inference: From the above conditions Case 1 is cancelled here as D will not pay the second lowest amount.
Clue: Person who pays second highest amount will have to pay Rs. 1500.
Inference: Final arrangement:
No one buys costlier ticket than M.
Q21. Who among the following persons has as many persons buys before him as after him?
(A). Z
(B). M
(C). D
(D). U
(E). None of these
Answer: C
Solution:
Explanation:
Clues: Only one person pays more amount than C. Two persons pay between C and U. D either pays just higher amount or just lower amount than U.
Inference: From the above conditions there are two possibilities i.e., Case 1 and Case 2.
Clues: As many persons pays more amount than U as pay less amount than Z. B pays amount than I. B does not pay the highest amount. M is one of the persons.
Inference: Only one person remains i.e., M.
Clue: D does not pay the second lowest amount.
Inference: From the above conditions Case 1 is cancelled here as D will not pay the second lowest amount.
Clue: Person who pays second highest amount will have to pay Rs. 1500.
Inference: Final arrangement:
As many persons buys before D as after D
Q22. Find the odd one out.
(A). TVE
(B). MOL
(C). GIR
(D). QSJ
(E). LNM
Answer: d
Solution:
First letter is second preceding letter of second letter. Third letter is opposite letter of second letter.
Study the following information carefully and answer the questions given below:
There are eight persons M, N, O, P, Q, R, S and T who were born either at 15th or 27th in four d i fferent months i.e. June, July, August and September. (not necessarily in same order). They like different brand of watches i.e. Rolex, Fossil, Seikos and Fastrack. (not necessarily in same order). Each of the two person likes the same languages. There were three persons born between P and the person who was born on 27th. Q was born just before the person who was born in the month of 30 days. There were asmany persons were born between Q and P as T and S. T was born just after P who likes Fastrack. There were three persons born between the persons who like the same brand. N was born on the month in which 31 days and born just before the person who likes Fastrack. R likes Fossil born just before N. M doesn’t like Fossil and Fastrack. No one born before the person who likes Rolex. Neither S nor T likes Seikos. Q born before M
Q23. Four of the following five are alike in certain way based from a group, find the one which does not belong to that group?
(A). Q-Seikos
(B). P-Fossil
(C). O-Fastrack
(D). N-Rolex
(E). T-Seikos
Answer: A
Solution:
From the given statements, there were three persons born between P and the person
who was born on 27th . T was born just after P who likes Fastrack. Here, we get three
possibilities i.e. Case 1, Case 2 and Case 3. There were three persons born between the
persons who like the same brand. N was born on the month in which 31 days and born
just before the person who likes Fastrack.
From the given statements, R likes Fossil born just before N. There were three persons
born between the persons who like the same brand. No one born before the person
who likes Rolex. Neither S nor T likes Seikos. Here, Case 1 and Case 2 are ruled out. Q
was born just before the person who was born in the month of 30 days. Q born before
M. M doesn’t like Fossil and Fastrack. There were as many persons were born between
Q and P as T and S.
So, final arrangement will be:
Q24. Which of the following is true?
(A). Q-Fossil
(B). R-Rolex
(C). M-Seikos
(D). T-Fastrack
(E). S-Seikos
Answer: C
Solution:
From the given statements, there were three persons born between P and the personwho was born on 27th . T was born just after P who likes Fastrack. Here, we get three possibilities i.e. Case 1, Case 2 and Case 3. There were three persons born between the persons who like the same brand. N was born on the month in which 31 days and born just before the person who likes Fastrack.
From the given statements, R likes Fossil born just before N. There were three persons born between the persons who like the same brand. No one born before the person who likes Rolex. Neither S nor T likes Seikos. Here, Case 1 and Case 2 are ruled out. was born just before the person who was born in the month of 30 days. Q born before M. M doesn’t like Fossil and Fastrack. There were as many persons were born between Q and P as T and S.
So, final arrangement will be: -
Q25. How many persons were born between Q and O?
(A). One
(B). Two
(C). Three
(D). More than three
(E). None
Answer: D
Solution:
From the given statements, there were three persons born between P and the person who was born on 27th . T was born just after P who likes Fastrack. Here, we get three possibilities i.e.Case 1, Case 2 and Case 3. There were three persons born between the persons who like the same brand. N was born on the month in which 31 days and born just before the person who likes Fastrack.
From the given statements, R likes Fossil born just before N. There were three persons born between the persons who like the same brand. No one born before the person who likes Rolex. Neither S nor T likes Seikos. Here, Case 1 and Case 2 are ruled out. Q was born just before the person who was born in the month of 30 days. Q born before M. M doesn’t like Fossil and Fastrack. There were as many persons were born between Q and P as T and S.
So, final arrangement will be: -
Q26. When was O born as per given information?
(A). 27th June
(B). 15th September
(C). 27th August
(D). 15th August
(E). None of these
Answer: C
Solution:
From the given statements, there were three persons born between P and the person who was born on 27th . T was born just after P who likes Fastrack. Here, we get three possibilities i.e. Case 1, Case 2 and Case 3. There were three persons born between the persons who like the same brand. N was born on the month in which 31 days and born just before the person who likes Fastrack.
From the given statements, R likes Fossil born just before N. There were three persons born between the persons who like the same brand. No one born before the person who likes Rolex. Neither S nor T likes Seikos. Here, Case 1 and Case 2 are ruled out. Q was born just before the person who was born in the month of 30 days. Q born before M. M doesn’t like Fossil and Fastrack. There were as many persons were born between Q and P as T and S.
So, final arrangement will be: -
Q27. Who among the following was born on 15th August?
(A). Q
(B). P
(C). T
(D). R
(E). M
Answer: C
Solution:
From the given statements, there were three persons born between P and the person who was born on 27th . T was born just after P who likes Fastrack. Here, we get three possibilities i.e. Case 1, Case 2 and Case 3. There were three persons born between the persons who like the same brand. N was born on the month in which 31 days and born just before the person who likes Fastrack.
From the given statements, R likes Fossil born just before N. There were three persons born between the persons who like the same brand. No one born before the person who likes Rolex. Neither S nor T likes Seikos. Here, Case 1 and Case 2 are ruled out. Q was born just before the person who was born in the month of 30 days. Q born before M. M doesn’t like Fossil and Fastrack. There were as many persons were born between Q and P as T and S.
So, final arrangement will be: -
Study the following information carefully and answer the questions given below:
Uncertain number of persons are sitting in a linear row facing north. Seven persons sit between W and L. V sits immediate left of L. Only four persons sit between V and P who sits at one of the extreme ends. A sits nine persons away from Z who sits exactly between P and W. More than three persons sits between A and P. The number of persons sits between A and W is two less than the number of persons sit between Z and N. K sits third to the left of N. Only two persons sit between K and J
Q28. If J sits second from one of the ends, then how many persons sit in the row?
(A). 19
(B). 20
(C). 22
(D). 24
(E). 23
Answer: A
Solution:
Final arrangement:
J A K W N Z V L P
↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑
Clues: Seven persons sit between W and L. V sits immediate left of L. Only four persons sit between V and P who sits at one of the extreme ends.
Inference: We have two possible cases
Case 1: W V L P
↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑
Case 2: P V L W
↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑
Clue: A sits nine persons away from Z who sits exactly between P and W. More than three persons sits between A and P.
Inference:
A W Z V L P
↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑
P V L Z W A
↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑
Clues: The number of persons sits between A and W is two less than the number of persons sit between Z and N. K sits third to the left of N. Only two people sit between K and J.
Inference: Case 2 gets eliminated
Case 1:
J A K W N Z V L P
↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑
Case 2:
P V L Z K N W A
↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑
Inference: The final arrangement is:
J A K W N Z V L P
↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑
18 persons + 1 (left of J since, J is 2nd from the end) = 19 persons.
Q29. How many persons sit between J and V?
(A). 14
(B). 16
(C). 11
(D). 17
(E). 13
Answer: C
Solution:
Final arrangement:
J A K W N Z V L P
↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑
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