Top 30 SBI PO Quantitative Aptitude Questions with Detailed Solutions

The SBI PO Quantitative Aptitude section for the 2026 Prelims is designed to evaluate a candidate's speed, precision, and analytical skills. With 35 questions to be completed in just 20 minutes, it remains one of the most demanding segments of the entire examination.

Most Important SBI PO Quantitative Questions

Solving these top 30 SBI PO Quantitative Aptitude practice questions is crucial for every serious aspirant. This set covers high-yield topics, including Number Series, Simplification, Approximation, Data Interpretation (Bar Graphs, Line Graphs, Tables, and Pie Charts), Quadratic Equations, and essential Arithmetic word problems—such as Percentages, Profit and Loss, Interest, Time and Work, Speed, Distance, and Ratio.

Q1. Sushma invested in two schemes, A and B, in a 5:7 ratio for two years. Scheme A offers 20% p.a. compound interest, while Scheme B provides 15% p.a. simple interest. If the difference between the interest earned from both schemes is Rs. 1520, what was the amount invested in Scheme A?

(A). Rs. 72,200
(B). Rs. 74,200
(C). None of these
(D). Rs. 75,500
(E). Rs. 76,000

Answer: E

Solution: Given: Scheme A (20% p.a. compound interest) and Scheme B (15% p.a. simple interest). The interest difference between the two schemes is Rs. 1520.

Q2. Vessel P contains a mixture of alcohol and water in a 4:7 ratio, while Vessel Q contains them in a 4:5 ratio. Both vessels are poured into a larger container, X. If the total quantity in X is 236 liters and the amount of water in P and Q was initially equal, determine the quantity of alcohol in Vessel P.

(A). 20 liters
(B). 56 liters
(C). 36 liters
(D). 40 liters
(E). 70 liters

Answer: D

Solution: Given: Vessel P mixture ratio is 4:7; Vessel Q mixture ratio is 4:5.

Q3. Solve for the missing value (?):
624/? + 169 = 51.98% of 400.01

(A). 4
(B). 12
(C). 8
(D). 32
(E). 16

Answer: E

Solution:

624/? + 169 = 0.52 × 400
624/? = 208 - 169
? = 624/39
? = 16

Q4. Ravi completes three-fourths of a work in 13.5 hours, while Hira completes two-thirds of the same work in 8 hours. If they work together, how long will it take to finish the entire project?

(A). 8h
(B). 7.2h
(C). 8.4 h
(D). 9 h
(E). 9.2 h

Answer: B

Solution:

Information: Ravi's time for 3/4 work = 27/2 hours. Hira's time for 2/3 work = 8 hours.

Formula Used: Total Work = Efficiency × Time

Explanation: Ravi completes the whole work in (4/3) × (27/2) = 18 hours. Hira completes the whole work in (3/2) × 8 = 12 hours. Required time = (18 × 12) / (18 + 12) = 216 / 30 = 7.2 hours.

Q5. The lengths of train A and train B are in a 5:4 ratio. Find the length of train A (in meters).
Statement (I): Both trains run in opposite directions; train A speed is 108 km/h. They cross each other in 20 seconds.
Statement (II): Train B runs at 72 km/h and crosses a 240 m long platform in 24 seconds.

(A). I alone
(B). II alone
(C). Both I & II together
(D). Either I or II
(E). Neither I nor II

Answer: B

Solution: Let lengths be 5x and 4x. From Statement (II), train B speed = 20 m/s. Crossing platform: 4x + 240 = 20 × 24 = 480. 4x = 240, so x = 60. Train A length = 5 × 60 = 300 meters. Statement (II) is sufficient.

Q6. A pump empties a 2400 m³ tank. Its emptying capacity is 10 m³/min higher than its filling capacity, and it takes 8 minutes less to empty than to fill. What is the filling capacity?

(A). 54
(B). 60
(C). 50
(D). 45
(E). 65

Answer: C

Solution:

Given: Capacity = 2400 m³. Let filling rate = x. Emptying rate = x + 10. (2400/x) - (2400/(x+10)) = 8. Solving for x yields 50 m³/min.

Q7. Solve for ?:
? × (20.01% of 580.01 + √196.01) = 729 + 51

(A). 6
(B). 4
(C). 2
(D). 8
(E). 12

Answer: A

Solution:

? × (0.20 × 580 + 14) = 780
? × (116 + 14) = 780
? × 130 = 780
? = 6

Q8. Ritika marked a jacket 20% above its cost price. Find the cost price.
Statement (I): A discount of Rs 40 resulted in a 10% profit.
Statement (II): Two successive discounts of 15% and 10% would cause a loss of Rs 32.8.

(A). I alone
(B). II alone
(C). Both I & II together
(D). Either I or II
(E). Neither I nor II

Answer: D

Solution:

Let CP = 100x, MP = 120x. From (I): (120x - 40) = 110x => 10x = 40 => x = 4. CP = 400. From (II): Successive discount of 15% and 10% = 120x * 0.85 * 0.9 = 91.8x. 100x - 91.8x = 32.8 => 8.2x = 32.8 => x = 4. CP = 400. Either is sufficient.

Study the table below showing total females and male-to-female ratios across five companies and answer the questions.

The provided table lists total females and the male-to-female ratio across five organizations.

Q9. In company F, females are 20% more than in A, and males are 20% fewer than the females in F. Find the difference in total employees between F and E.

(A). 56
(B). 48
(C). 29
(D). 40
(E). 57

Answer: A

Solution:

In A, males:females = 7:5. If 5x = 25, then x = 5. Males = 35. Total = 60.

Females in F = 1.2 × 25 = 30. Males in F = 0.8 × 30 = 24. Required diff = 110 - (30+24) = 56.

Q10. Find the average number of males in companies D and B.

(A). 39
(B). 38
(C). 35
(D). 40
(E). 37

Answer: A

Solution:

Calculation based on company data provided in the set.

Required average = (48 + 30) / 2 = 39.

Q11. The promoted-to-non-promoted employee ratio in D is 2:3. If 25 females are promoted, what percentage are they of the non-promoted females in D?

(A). 11.11
(B). 22.22
(C). 33.33
(D). 44.44
(E). 55.55

Answer: E

Solution:

Calculations based on employee distributions in company D.

Promoted = 40, Non-promoted = 60. Promoted females = 25. Non-promoted females = 70 - 25 = 45. Required = (25/45) * 100 = 55.55%.

Q12. Find the ratio of total employees in A to the males in B & D combined.

(A). 5:6
(B). 4:9
(C). 10:13
(D). 14:13
(E). 5:7

Answer: C

Solution:

Calculation based on total workforce data.

Required ratio = 60 : (48 + 30) = 60 : 78 = 10 : 13.

Q13. Find the difference between the total males and total females in all companies.

(A). 102
(B). 108
(C). 109
(D). 106
(E). 100

Answer: D

Solution:

Summing total male and female counts from the dataset.

Required difference = 312 - 206 = 106.

Q14. In C, the ratio of intern to permanent employees is 1:1. Given 25 female interns, find the number of permanent male employees in C.

(A). 1
(B). 2
(C). 3
(D). 4
(E). 5

Answer: E

Solution:

Analysis of company C staffing.

Total intern = 68. Male interns = 68 - 25 = 43. Total permanent = 48. Permanent males = 48 - 43 = 5.

Q15. The average of 8 numbers is 39.5. When two new numbers are added, the average decreases by 2.5. If the new numbers are in a 2:1 ratio, find the larger of the two.

(A). 28
(B). 18
(C). 27
(D). 36
(E). None of these

Answer: D

Q16. A sum (x) invested at 10% simple interest for 3 years fetches Rs. 120 more when invested at 14% for the same duration. Find 5x.

(A). 5000
(B). 4800
(C). 3600
(D). 5500
(E). 4000

Answer: A

Solution:

Principal = x. Rate 1 = 10%, Time = 3.

Rate 2 = 14%. Interest difference = Rs. 120.

Formula: SI = (P × R × T) / 100.

Difference = x * 3 * (0.14 - 0.10) = 120. 0.12x = 120. x = 1000. 5x = 5000.

Q17. Solve for ?:
1248.01 + ? = 96.01% of 1525.01

(A). 6
(B). 5
(C). 4
(D). 10
(E). 12

Answer: A

Analyze the pie charts showing student distribution and female counts across four colleges to answer the following questions.

Q18. Find the average number of males in B, C, and D.

(A). 240
(B). 120
(C). 360
(D). 100
(E). 150

Answer: A

Solution:

Calculation of male distribution in B, C, and D.

Required average = (200 + 30 + 490) / 3 = 240.

Q19. Find the ratio of males in C and D together to females in A and C together.

(A). 24:25
(B). 52:35
(C). 35:36
(D). 9:10
(E). 15:14

Answer: B

Solution:

Extraction of data values.

Ratio = (30+490) : (130+220) = 520 : 350 = 52 : 35.

Q20. Total females in C and B is what percentage of total students in D?

(A). 84.25%
(B). 82%
(C). 81.25%
(D). 100%
(E). 81.2%

Answer: C

Solution:

Calculation of female population in B and C.

Percentage = (300 + 220) / 640 * 100 = 81.25%.

Q21. In college E, students = 3X (35% are female). Are males in E more or less than total students in B? By what percentage?

(A). 15%
(B). 12%
(C). 16%
(D). 10%
(E). 17%

Answer: E

Solution:

Calculation of students in E.

Total in E = 900. Females = 315. Males = 585. % Diff = (585 - 500) / 500 = 17%.

Q22. Find the difference between the total students in A & B combined and twice the males in B.

(A). 740
(B). 720
(C). 760
(D). 710
(E). 750

Answer: D

Solution:

Data retrieval.

Difference = (610 + 500) - 2(200) = 710.

Read the business partnership information provided below to answer the following questions.

A, B, and C started a business. Investment ratio A:B = 11:9. C invested 33.33% more than B. Time periods: A (8 months), B (6 months), and C (12 months).

Q23. If A's investment is Rs 1650, what is the investment of C?

(A). 1500
(B). 1350
(C). 1800
(D). 1650
(E). 2100

Answer: C

Solution:

Let A=11x, B=9x. C = (4/3) * 9x = 12x. Investment of C = 1650 * (12/11) = 1800 Rs.

Q24. Given a total annual profit of Rs 4290, what is the profit share of B?

(A). 860
(B). 950
(C). 810
(D). 740
(E). 1020

Answer: C

Solution:

Profit ratio = (11*8):(9*6):(12*12) = 88:54:144 = 44:27:72. Total parts = 143. Share of B = 4290 * (27/143) = 810.

Q25. If the profit share of C is Rs 1080, what is the profit share of A?

(A). 710
(B). 840
(C). 920
(D). 600
(E). 660

Answer: E

Solution:

Using profit ratio 44:72. Share of A = 1080 * (44/72) = 660.

Q26. A rectangle's length is 4 cm more than its breadth, and its area is 96 cm². A square has a side 6 cm more than the rectangle's length. Find the square's area.

(A). 256
(B). 324
(C). 225
(D). 361
(E). 144

Answer: B

Q27. P, Q, and R start a business. P invests 40%, Q 20%, and R the remainder. P receives Rs 5760 as profit. What is the total business profit?

(A). 15960
(B). 14480
(C). 15840
(D). 13840
(E). 15560

Answer: C

Solution:

Investment ratio: 40:20:40 = 2:1:2. Time: 8, 4, 12 months.

Formula: Profit share = Investment × Time.

Ratio P:Q:R = (2*8):(1*4):(2*12) = 16:4:24 = 4:1:6. Profit = (5760/4) * 11 = 15840.

Q28. A spends 20% on rent and 25% of the remainder on travel. He splits the rest between food and education in a 3:5 ratio. If the education-rent difference is Rs 700, find his salary.

(A). 2500
(B). 4000
(C). 4500
(D). 5000
(E). 2000

Answer: B

Solution:

Rent = 20%. Remainder = 80%. Travel = 25% of 80 = 20%. Remaining = 60%.

Formula: Successive percentage calculation.

Salary = 100x. Rent = 20x. Travel = 20x. Food + Edu = 60x. Food = 22.5x, Edu = 37.5x. 37.5x - 20x = 700 => 17.5x = 700 => x = 40. Salary = 4000.

Q29. A boat covers D km downstream in 2T hours and (D-400) km in still water in T hours. Speed of boat = 6x current speed. Find D.

(A). 750
(B). 710
(C). 740
(D). 730
(E). 700

Answer: E

Solution:

Current = x, Boat = 6x. Downstream = 7x. D/(2T) = 7x => D=14Tx. Still water = 6x. (D-400)/T = 6x => D-400=6Tx. Subbing 14Tx for D: 14Tx - 400 = 6Tx => 8Tx = 400 => Tx=50. D = 14*50 = 700.

Q30. Two years ago, Raju was 75% of Rita's age. In two years, Rita will be 33 1/3% of her father's age. Father and mother average 31 yrs; mother is 28. What is Raju's present age?

(A). 10 yrs
(B). 6 yrs
(C). 8 yrs
(D). 12 yrs
(E). 14 yrs

Answer: C

Solution:

Information compilation.

Raju's age (T-2) = 0.75 * Rita (T-2).

Explanation:

Father = 62 - 28 = 34. Rita (T+2) = 1/3 * 36 = 12. Rita present = 10. Raju present = (10-2)*0.75 + 2 = 8.